15
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
56.
56
the product of 56 and 7 is 392
15
The product of 8 & 7 is 56 (8x7=56)
56 is the answer
56 because 7 x 8 = 56
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
To find the product of 4 over 7 (4/7) and 56, you simply multiply the two numbers together. This can be done by multiplying the numerators (4 * 56) and the denominators (7 * 1) separately. Therefore, the product of 4/7 and 56 is (4 * 56) over (7 * 1), which simplifies to 224 over 7 or 32.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
56.
56
56.