To find the product of the prime factors of 10,800, we first need its prime factorization. The prime factorization of 10,800 is (2^4 \times 3^3 \times 5^2). The distinct prime factors are 2, 3, and 5. Therefore, the product of the primes is (2 \times 3 \times 5 = 30).
10,800 = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 5 x 5 or 24 x 33 x 52
95 is the product of two primes, 5 and 19.
1361
98=2x7x7
2x2x7x7x11=2156
There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.
10,800 = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 5 x 5 or 24 x 33 x 52
The products of the primes are the composites.
1450 as a product of primes = 2 * 5 * 5 * 29
20 as a product of primes = 2 * 2 * 5
95 is the product of two primes, 5 and 19.
40
2x2x2x2x2x2
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2x2x5x5
1361
5x7