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What quadrant will the area be if x equals and greater than 0 and y equals and less than 0?
Quad IV x is right side, y is down.
What quadrant does y equals 6x pass through?
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
Why does quadrant 2 come before quadrant 1?
It doesn't. Its a matter of interpretation. When drawing the unit circle, we start at x=1, y=0. As we draw, maintaining a radius of 1 from the origin at x=0, y=0, we proceed counter-clockwise. Initially, both x and y are positive. That is quadrant 1. When x becomes negative at x=0, y=1, that is quadrant 2. When y becomes negative at x=-1, y=0, that is quadrant 3. And when x becomes positive again at x=0, y=-1, that is quadrant 4. So you see, its all in the perspective of which comes first, and in trigonometry, the vector where theta = 0 comes first, not where your eye just happens to scan from left to right.
Which quadrant contains -3 0?
Points on the x-axis or y-axis are not in any quadrant. Therefore, (-3,0) is not contained in a quadrant.
How do you solve y-2y'-3y equals 0?
For y - 2y - 3y equals 0, y equals 0.
What quadrant will the area be if x equals and greater than 0 and y equals and less than 0?
Quad IV x is right side, y is down.
How do you solve quadrants with special sides?
The coordinate or Cartesian plane is divided into four quadrants by the axes. The axes, themselves, do not belong to any quadrant. Assuming the normal x and y-axes, Quadrant I : x > 0, y > 0 Quadrant II : X < 0, y > 0 Quadrant III : X < 0, y < 0 Quadrant IV: X > 0, y < 0 That's it. No special sides, nothing to solve.
Identify the quadrant in which the point x y lies if x 0 and y?
If x = 0 then the point is on the y-axis and so it not in any quadrant.
What is the compound inequalities for the four quadrants of the cartesian coordinate system?
Quadrant I: x > 0, y > 0 Quadrant II: x < 0, y > 0Quadrant I: x < 0, y < 0Quadrant I: x > 0, y < 0
What quadrant does y equals 6x pass through?
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
What quadrant will the area be if x 0 and y is 0?
Origin
What are the values of quadrant 2?
X < 0 and y > 0.
Which diagram shows the graph of y equals -x-3?
I can not graph for you, but two points can be found. Zero out X and Y. -X - 3 = 0 -X = 3 X = - 3 Y = - 3, of course Draw a line from the second quadrant into the third quadrant and through the fourth quadrant connecting these two points into a descending line.
In a line graph what quadrant is y equals -9?
Third and fourth
On a graph what does the line look like for y equals 9 - 2 x?
7
Why does quadrant 2 come before quadrant 1?
It doesn't. Its a matter of interpretation. When drawing the unit circle, we start at x=1, y=0. As we draw, maintaining a radius of 1 from the origin at x=0, y=0, we proceed counter-clockwise. Initially, both x and y are positive. That is quadrant 1. When x becomes negative at x=0, y=1, that is quadrant 2. When y becomes negative at x=-1, y=0, that is quadrant 3. And when x becomes positive again at x=0, y=-1, that is quadrant 4. So you see, its all in the perspective of which comes first, and in trigonometry, the vector where theta = 0 comes first, not where your eye just happens to scan from left to right.
Which quadrant contains -3 0?
Points on the x-axis or y-axis are not in any quadrant. Therefore, (-3,0) is not contained in a quadrant.
