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What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
How do you solve 4x2 - 4x plus 2 equals 0?
If you can't factor it easily, use the quadratic formula.
What're examples of quadratic equation?
x*2+4x+8= 0 is a quadratic equation
Explain why x2 plus 4x plus 4 equals 0 has 2 x intercepts?
x2+4x+4 = 0 (x+2)(x+2) = 0 x = -2 and also x = -2 When the solutions to a quadratic equation are identical this means that both values are at the turning point or vertex of the parabola just on the x axis. d>=0,then roots of quadratic equation are real if D<0,then roots are imaginary
X2 - 4x equals -4?
x2 - 4x + 4 = 0 (x - 2)(x - 2) = 0 x = 2
What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
How do you solve 4x2 - 4x plus 2 equals 0?
If you can't factor it easily, use the quadratic formula.
Can anyone help with this problem solve Quadratic problem 3x2 4X -2 0?
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
What're examples of quadratic equation?
x*2+4x+8= 0 is a quadratic equation
Is 4x plus 5c plus 10c-3x equals 0a quadratic equation?
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
How do you solve -4x-2 equals -2?
-4x-2+2=-2+2. -4x/-4=0/-4 x=0
Identify the number of solutions to the quadratic equation 4x2 - 4x plus 1 equals 0?
4x2 - 4x + 1 = 0 => (2x - 1)(2x - 1) = 0 => (2x - 1)2 = 0 There is one solution: x = 1/2. It is a repeated root of the equation.
Explain why x2 plus 4x plus 4 equals 0 has 2 x intercepts?
x2+4x+4 = 0 (x+2)(x+2) = 0 x = -2 and also x = -2 When the solutions to a quadratic equation are identical this means that both values are at the turning point or vertex of the parabola just on the x axis. d>=0,then roots of quadratic equation are real if D<0,then roots are imaginary
How do you solve X2 plus 4x plus 2 equals 0?
x^2 + 4x + 2 = 0 doesn't factor neatly. Using the quadratic formula, we find two solutions: -2 plus or minus the square root of 2 x = -0.5857864376269049 x = -3.414213562373095
X2 - 4x equals -4?
x2 - 4x + 4 = 0 (x - 2)(x - 2) = 0 x = 2
Solve 2x2 plus 4x-9 equals 0?
2*2+4x-9=0 4x=9-4 4x=5 x=5/4
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
