41 - 9 = 32
19 + 3 = 22
To find the mean of the set (15, 22, 19, 20, 29, 18, 25, 19, 31), first sum the numbers: (15 + 22 + 19 + 20 + 29 + 18 + 25 + 19 + 31 = 208). There are 9 numbers in the set, so the mean is ( \frac{208}{9} \approx 23.11). Thus, the mean of the set is approximately (23.11).
Average = sum(X)/n = 60/3 = 20
18.
2,870,795,128,037,760 or approx 2.871*1015
The quotient of 18 and 2 is 9 The sum of 22 and 9 is 31 31-9=22
22
18+19+20+21+22
The numbers are 18, 19, 20, 21 and 22.
19 + 3 = 22
The mean = The sum of all the values ÷ The number of values. 18 + 15 + 22 + 18 + 25 + 19 + 23 = 140 : Number of values = 7 Mean = 140 ÷ 7 = 20
When you divide 418 by 22, you get 19. This is because 418 divided by 22 equals 19 with no remainder. In mathematical terms, the quotient of 418 divided by 22 is 19.
18 + 4 = 22
To find the mean of the set (15, 22, 19, 20, 29, 18, 25, 19, 31), first sum the numbers: (15 + 22 + 19 + 20 + 29 + 18 + 25 + 19 + 31 = 208). There are 9 numbers in the set, so the mean is ( \frac{208}{9} \approx 23.11). Thus, the mean of the set is approximately (23.11).
The median is 19.
19 and 3; 17 and 5.
Average = sum(X)/n = 60/3 = 20