It is the upper quartile minus the lower quartile.
No, interquartile range cannot be for any data. The lower quartile for data must be used below the lower quartile.
If the result is 1.5 x Inter Quartile Range (or more) above the Upper Quartile or 1.5 x Inter Quartile Range (or more) below the Lower Quartile.
There is no need to lose your rag!It is the inter-quartile range.
The interquartile range is the difference between the Lower quartile and the upper quartile. Obviously you need to be able to find these values. Haylock (2006) explains how to do this for difficult size groups in mathematics explained for primary teachers. He explains the position of the lower quartile is a quarter of (n+1) and that of the upper quartile is three-quarters of (n+1). So for a group of 7 numbers, you find a quarter of 8, which is 2. Therefore the number in second place is the lower quartile. Three quarters of 8 is 6 and so the number in 6th position is the upper quartile. Now take the lower quartile from the upper quartile.
Interquartile Range, or IQR
The interquartile range of a set of data is the difference between the upper quartile and lower quartile.
Subtract the lower quartile from the upper quartile.
IQR = Inter-Quartile Range = Upper Quartile - Lower Quartile.
It is the upper quartile minus the lower quartile.
the interquartile is just subtracting the high quartile from the low quartile. * * * * * No, it is subtracting the lower quartile from the higher quartile.
No, interquartile range cannot be for any data. The lower quartile for data must be used below the lower quartile.
the range is also known as the IQR or inner quartile range's. The inter quartile range is the difference between the upper quartile and the lower quartile.heresy a good example.Example:18 27 34 52 54 59 61 68 78 82 85 87 91 93 100~First find the median -----> 68~then the lower quartile --> 52~next the upper quartile --> 87after you find these you may subtract the lower quartile (aka UQ) from the upper quartile (aka the UQ)In our case the IQR = 87 - 52 = 35.
If the result is 1.5 x Inter Quartile Range (or more) above the Upper Quartile or 1.5 x Inter Quartile Range (or more) below the Lower Quartile.
There is no need to lose your rag!It is the inter-quartile range.
Consider the data: 1, 2, 2, 3, 4, 4, 5, 7, 11, 13 , 19 (arranged in ascending order) Minimum: 1 Maximum: 19 Range = Maximum - Minimum = 19 - 1 = 18 Median = 4 (the middle value) 1st Quartile/Lower Quartile = 2 (the middle/median of the data below the median which is 4) 3rd Quartile/Upper Quartile = 11 (the middle/median of the data above the median which is 4) InterQuartile Range (IQR) = 3rd Quartile - 1st Quartile = 11 - 2 = 9
interquartile range is upper quartile (or quartile 3) minus lower quartial ( or quartial 1 ) For example the quartile 3 is 165 and the quartile 1 is 125. The interquartile range is 40. You can go online and see pages. Thank you