Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question.
If the expression in the question is meant to be the equation y = 3x - 2, then the range is {7, 13, 19}.
Otherwise, please resubmit your question spelling out the symbols as "plus", "minus", "equals".
(2x+3) / 5 Domain = All Real Numbers Range = All Real Numbers
domain: all real numbers range: {5}
Yes. The range can have fewer number of entries.As an extreme case, consider f(x) = 3, where x is a Real number.The domain is all Real numbers - infinitely many of them, while the range is one value: 3.A function can contain one-to-one or many-to-one relationships but one-to-many relationships are not permitted. As a result, the cardinality of the range cannot be bigger than the cardinality of the domain.
To find the domain and range in ordered pairs, first, identify the set of all first elements (x-values) from each ordered pair for the domain. For the range, identify the set of all second elements (y-values) from the same pairs. For example, in the ordered pairs (2, 3), (4, 5), and (2, 6), the domain is {2, 4} and the range is {3, 5, 6}. Make sure to list each element only once in the final sets.
7
(2x+3) / 5 Domain = All Real Numbers Range = All Real Numbers
Find all possible "x" and "y" values for domain and range. Then put it in inequality form. For example the domain and range for the equation 2x-3/x-5 would be: Domain: All Reals; x>5 Range: All Reals
-3
domain: all real numbers range: {5}
You can define the domain as anything you like and that will determine the range. Or, you can define the range as anything you like and that will determine the domain. For example: domain = {1, 2, 3, 4, ... } then range = {-3, 0, 5, 12, ... } or range = {1, 2, 3, 4, ... } then domain = {sqrt(5), sqrt(6), sqrt(7), sqrt(8), ...}. There is, of course, no need to restrict either set to integers but then it was easier to work out one set from the other.
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
The range is {-5, -2, 1, 4}
x y -3 2 -1 6 1 -2 3 5
What is the domain and range of absolute lxl - 5
Yes. The range can have fewer number of entries.As an extreme case, consider f(x) = 3, where x is a Real number.The domain is all Real numbers - infinitely many of them, while the range is one value: 3.A function can contain one-to-one or many-to-one relationships but one-to-many relationships are not permitted. As a result, the cardinality of the range cannot be bigger than the cardinality of the domain.
To find the domain and range in ordered pairs, first, identify the set of all first elements (x-values) from each ordered pair for the domain. For the range, identify the set of all second elements (y-values) from the same pairs. For example, in the ordered pairs (2, 3), (4, 5), and (2, 6), the domain is {2, 4} and the range is {3, 5, 6}. Make sure to list each element only once in the final sets.
7