koh + h2so4-khso4 +h2o
If the ratio of similarity is 310, then the ratio of their area is 96100.
an eqivalent ratio is an ratio that is equal or you can simplfiy it
Unit Ratio- a ratio that has a denominator of 1
There is no single ideal ratio.
That would depend upon the lab technician.
2 moles of NaOH are required to neutralize 1 mole of H2SO4 because the reaction between NaOH and H2SO4 is 2:1 molar ratio.
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
To find the concentration of H2SO4, first calculate the number of moles of NaOH using the formula: moles = concentration x volume (in dm^3). Then, use the balanced equation to determine the mole ratio between NaOH and H2SO4. Finally, calculate the concentration of H2SO4 by dividing the moles of H2SO4 by the volume of H2SO4 used.
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
Sulfuric acid itself is a compound with the formula H2SO4. However the word "dilute" means that the H2SO4 is dissolved in water, so it is a mixture.
There are 1.68 x 10^24 atoms of sulfur in 280g of a 50% H2SO4 solution. This can be calculated by first finding the moles of H2SO4 in the solution, then using the molar ratio to find the moles of sulfur, and finally converting moles to atoms using Avogadro's number.
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
To find the volume of 0.270 M H2SO4 needed to react with 46.0 mL of 0.100 M NaOH, you need to use the stoichiometry of the balanced equation. The balanced equation tells you that 1 mole of H2SO4 reacts with 2 moles of NaOH. From this information, you can set up a ratio using the concentrations and volumes of the two solutions to calculate the volume of 0.270 M H2SO4 needed.
First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)
The balanced equation for the reaction is: 3H2SO4 + 2Al(OH)3 -> Al2(SO4)3 + 6H2O. From the balanced equation, the mole ratio of H2SO4 to H2O is 3:6, which simplifies to 1:2.