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The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
What else can I help you with?
What is the answer to this number sequence 1 4 13 40?
121
What number comes next in the sequence 4 13 40 121?
22
What are the next two numbers in this series 1 4 13 40 121?
364
What is the pattern 1 4 13 40?
To get the next term, triple the present term and add 1 . The next term after 40 is 121 .
What are the next two numbers of this series 1 4 13 40 121 364?
1,093 3,2804 - 1 = 313 - 4 = 940 - 13 = 27121 - 40 = 81364 - 121 = 243each difference is 3 times the previous243 x 3 = 729 then 364 + 729 = 1,093729 x 3 = 2,187 then 1,093 + 2,187 = 3,280
What is the answer to this number sequence 1 4 13 40?
121
What number comes next in the sequence 4 13 40 121?
22
What are the next two numbers in this series 1 4 13 40 121?
364
What is the pattern 1 4 13 40?
To get the next term, triple the present term and add 1 . The next term after 40 is 121 .
What are the factors of 121 and 143?
The factors of 121 are 1, 11, 121 The factors of 280 are 1, 2, 4, 5, 7, 8, 10, 14, 20, 28, 35, 40, 56, 70, 140, 280
What are the next two numbers of this series 1 4 13 40 121 364?
1,093 3,2804 - 1 = 313 - 4 = 940 - 13 = 27121 - 40 = 81364 - 121 = 243each difference is 3 times the previous243 x 3 = 729 then 364 + 729 = 1,093729 x 3 = 2,187 then 1,093 + 2,187 = 3,280
What is 3.025 as a fraction?
121/40
How many 3s go into 121?
121 divided by 3 equals 40 with a remainder of 1.
What must you add to 66 to make the sum of 121?
The number is 55+66 = 121
What is 42 plus 79?
42 + 79 = 121 (40+70) + (2+9) = = 110 + 11 = 121
How many times does 3 go into 121?
No
Can you find your blueprints for a standard 40 room hotel?
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