The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
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121
22
364
To get the next term, triple the present term and add 1 . The next term after 40 is 121 .
1,093 3,2804 - 1 = 313 - 4 = 940 - 13 = 27121 - 40 = 81364 - 121 = 243each difference is 3 times the previous243 x 3 = 729 then 364 + 729 = 1,093729 x 3 = 2,187 then 1,093 + 2,187 = 3,280