A right angle triangle with two side lengths that match that of an equivalent square will have exactly half the area of the square.
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I'll be happy to help you, but in order for me to compare the areas of those triangles, you have to tell me the areas of those triangles.
It depends on the symmetry. Work out the area of half the shape by filling the shape with squares and triangles of known areas and times the answer by two.
If 'S' is the relationship between actual and scale linear dimensions,then 'S2' is the relationship between actual and scale areas.
The formula depends on what shape you're working with. Triangles, circles, parallelograms, squares, trapezoids, ellipses, hexagons, prisms, cones, spheres, cylinders, etc. all have different formulas for their areas.
Not really, but that depends on what your definition of easy is. Try to divide the irregular quadrilateral into smaller regular pieces -- triangles and squares. You should be able to divide the shape into one square and two triangles. Then you can determine their areas and find the sum.