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If given that:

  • a, b, and c are sides for any triangle,
  • A, B, and C are the angles opposite of their sides,
  • assuming c is the longest side, then

c2 = a2 + b2 -2ab*cos(C) (Law of Cosines)

c/sin(C) = a/sin(A) = b/sin(B) (Law of Sines)

In a right triangle,

a2 + b2 = c2(Pythagorean Theorem)

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