I assume you meant x^4 + 5x^2 +10x + 12.
The remainder is 28
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
To simplify the expression ((4x^2 - 10x + 2) \div (x - 3)), you can use polynomial long division. Dividing (4x^2 - 10x + 2) by (x - 3) gives you (4x - 2) with a remainder of (8). Therefore, the result is (4x - 2 + \frac{8}{x - 3}).
x2+10x-24 = (x-2)(x+12)
(x+1)(x+9)
(x - 5)(x - 5)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
To simplify the expression ((4x^2 - 10x + 2) \div (x - 3)), you can use polynomial long division. Dividing (4x^2 - 10x + 2) by (x - 3) gives you (4x - 2) with a remainder of (8). Therefore, the result is (4x - 2 + \frac{8}{x - 3}).
(x+1)(x+9)
x2+10x-24 = (x-2)(x+12)
x2+10x+21 = (x+3)(x+7)
(x+1)(x+9)
(x - 5)(x - 5)
6
The expression (-5x^3 + 10x^2) represents a polynomial in terms of (x). It consists of two terms: (-5x^3), which is a cubic term, and (10x^2), which is a quadratic term. This polynomial can be factored as ( -5x^2(x - 2) ).
Say x^4-5x^2-10x-12 = f(x)(x+2)+c. If we substitute x = -2 something magical happens: (-2)^4-5(-2)^2-10(-2)-12 = f(-2)(-2+2)+c 16-20+20-12 = f(-2)*0+c 4 = c So the remainder must be 4.
To factor the polynomial (2x^2 + 20x + 50), first, we can factor out the greatest common factor, which is 2. This gives us (2(x^2 + 10x + 25)). The quadratic (x^2 + 10x + 25) can be factored further as ((x + 5)^2). Thus, the complete factorization of the polynomial is (2(x + 5)^2).
45