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it adds one more each time. 1+2=3 3+3=6 6+4=10 10+5=15 the next one would be 15+6=21
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With U{n} = (7n⁵ - 105n⁴ + 595n³ - 1555n² + 1938n - 840)/40
U{1, ..., 5} = {1, 3, 6, 10, 15}
U{6} = 42
However, I suspect the rule your teacher wants is that it is the triangular numbers given by U{n} = ½n(n + 1)
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Simplest form of 15 over 10?
It is: 15/10 = 3/2
What is 1 over 5 plus 2 over 3?
1/5 = 3/15 2/3 = 10/15 3/15 + 10/15 = 13/15
What is the height of a rectangular based pyramid with a volume of three hundred cubic meters and base dimensions of fifteen meters and ten meters?
Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.
What is the answer of 2 over 3 plus 1 over 5?
2/3+1/5=10/15+3/15=(10+3)/15=13/15
What are the first fourth and tenth terms of the arithmetic sequence described by the given rule A(n) 12 plus (n-1) (3)?
A(1) = 12A(4) = 3 A(10) = -15.
