To find the nth number that is generated by the rule multiply n by 4 and then add 2.
5n-2+2=4n 5n=4n n=0
7n + 2 = 4n + 17Subtract 2 from each side:7n = 4n + 15Subtract 4n from each side:3n = 15Divide each side by 3:n = 5
3 + 3n = 9 + 2n + 4n n = -2
4n
2 - 4N = 2 + 3NSubtract 2 from each side:-4N = 3NAdd 4N to each side:0 = 7NN = 0That's the only value of ' N ' for which the given equationcan become a true statement.
5n-2+2=4n 5n=4n n=0
4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
7n + 2 = 4n + 17Subtract 2 from each side:7n = 4n + 15Subtract 4n from each side:3n = 15Divide each side by 3:n = 5
3 + 3n = 9 + 2n + 4n n = -2
4n
n is an integer that can be 0,1,2,3,... and so on. All this means is that for an aromatic ring to be aromatic it has to have pi bonds that are 2,6,10,14,18,... and so on. On the other hand a antiaromatic ring will have the formula 4n so that pi bonds are 4,8,12,16,20,... and so on.
2 - 4N = 2 + 3NSubtract 2 from each side:-4N = 3NAdd 4N to each side:0 = 7NN = 0That's the only value of ' N ' for which the given equationcan become a true statement.
8n-2+4n = 66-5n 8n+4n+5n = 66+2 17n = 68 n = 4
If 7m = 4n+2 and 7m+2 = 8 m = 6/7 and n = 1
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
4n
An equation