n*3; n-1 {Where "n" is the previous answer starting at 1.
1,
1*3=3,
3-1=2,
2*3=6,
6-1=5,
5*3=15,
15-1=14,
14*3=42,
42-1=41.
14.514.514.514.5
Oh, dude, it's like the pattern rule here is just adding 9, then multiplying by 3. So, you go from 5 to 14 by adding 9, then from 14 to 41 by multiplying by 3 and adding 5, and so on. But hey, who needs patterns when you have Netflix, am I right?
The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
multiplication pattern
It is 20*(14-12)+7-6 = 41
14.514.514.514.5
The prime numbers between 1 and 15 are 2, 3, 5, 7, 11, and 13. To find the sum, you simply add these numbers together: 2 + 3 + 5 + 7 + 11 + 13 = 41. Therefore, the sum of prime numbers between 1 and 15 is 41.
Oh, dude, it's like the pattern rule here is just adding 9, then multiplying by 3. So, you go from 5 to 14 by adding 9, then from 14 to 41 by multiplying by 3 and adding 5, and so on. But hey, who needs patterns when you have Netflix, am I right?
The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).
The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
41
1, 3, 5, 15, 41, 123, 205, 615.
Start at 1. Multiply by 3. Subtract 1. Multiply by 3. Subtract 1. Repeat this pattern.
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.