There are infinitely polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
However, the simplest rule here is
t(n) = n*(n+1) for n = 1, 2, 3, ...
Another Answer: nth term = n^2+n whereas n is the term number
y = x(x + 1)
5-30-6-42-7-56-8-72
The factors of 12 are 1, 2, 3, 4, 6, and 12. The factors of 20 are 1, 2, 4, 5, 10, and 20. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30. The greatest factor they all have in common is 2.
12, 18, 20, 24, 30
The answer is 20/30 = 2/3.The answer is 20/30 = 2/3.The answer is 20/30 = 2/3.The answer is 20/30 = 2/3.
It looks like it could be: 0 + 2 = 2 2 + 4 = 6 6 + 6 = 12 The next logical answers would be: 12 + 8 = 20 20 + 10 = 30 30 + 12 = 42 And so on...
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
y = x(x + 1)
5-30-6-42-7-56-8-72
A = 2(20*30) + 2(20*12) + 2(30*12) = 2(600 + 240 + 360) = 2*1,200 = 2,400 in2
12 : 12 : 6 30 = (12x2) + (6x1) so ratio will be 12 : 12 : 6 = 2 : 2 : 1
60 to 30 _ -1/2 30 to 20 _ -1/3 20 to 15 _ -1/4 15 to 12 _ -1/5 12 - (12*1/6) = 10
The factors of 12 are 1, 2, 3, 4, 6, and 12. The factors of 20 are 1, 2, 4, 5, 10, and 20. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30. The greatest factor they all have in common is 2.
12, 18, 20, 24, 30
Vertices = 20 Faces = 12 Edges = 30 V + F = 20 + 12 = 32 E + 2 = 30 + 2 = 32 So V + F = E + 2
1/2, 2/3. 3/4, 4/5, 5/6 1/2 of 60 = 30 2/3 of 30 = 20 3/4 of 20 = 15 4/5 of 15 = 12 5/6 of 12 = 10 The next number is 10
2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 6: 6, 12, 18, 24, 30 10: 10, 20, 30 LCM = 30