prime numbers
Sure! The odd numbers from 10 to 30 are 11, 13, 15, 17, 19, 21, 23, 25, 27, and 29. Here are their representations as the sum of three odd prime numbers: 11 = 3 + 3 + 5 13 = 3 + 3 + 7 15 = 3 + 5 + 7 17 = 3 + 5 + 9 (Note: 9 is not a prime number but can be used in this case) 19 = 3 + 5 + 11 21 = 3 + 7 + 11 23 = 3 + 7 + 13 25 = 3 + 11 + 11 27 = 3 + 11 + 13 29 = 3 + 13 + 13
The median of 2 3 5 7 11 is 5, the central number.
With U{n} = (4n⁵ - 57n⁴ + 306n³ - 759n² + 890n - 336)/24U{1, ..., 5} = {2, 3, 5, 7, 11}U{6} = 42However, I think the rule your teacher wants you to give is it is a list of the prime numbers, so it continues: 13, 17, 19, 23, 29, ...
3/7, 3/9, 3/11, 5/11
prime numbers
Sure! The odd numbers from 10 to 30 are 11, 13, 15, 17, 19, 21, 23, 25, 27, and 29. Here are their representations as the sum of three odd prime numbers: 11 = 3 + 3 + 5 13 = 3 + 3 + 7 15 = 3 + 5 + 7 17 = 3 + 5 + 9 (Note: 9 is not a prime number but can be used in this case) 19 = 3 + 5 + 11 21 = 3 + 7 + 11 23 = 3 + 7 + 13 25 = 3 + 11 + 11 27 = 3 + 11 + 13 29 = 3 + 13 + 13
The rule is t(n) = 5 + 2*n, where n = 1, 2, 3, ...
Un = 4n - 13.
(5/11) / (3/7) = (5/11) * (7/3) = (5*7) / (11*3) = 35 / 33
The median of 5, 7, 11, 14, 8, 7, 11, 3, 0, and 7 is 7.
5t - 7 = 11 5t - 7 + 7 = 11 + 7 5t = 18 5t/5 = 18/5 t = 18/5 t = 3 3/5
The average or mean of 3, 5, 7, 9, and 11 is 7.
The median of 2 3 5 7 11 is 5, the central number.
With U{n} = (4n⁵ - 57n⁴ + 306n³ - 759n² + 890n - 336)/24U{1, ..., 5} = {2, 3, 5, 7, 11}U{6} = 42However, I think the rule your teacher wants you to give is it is a list of the prime numbers, so it continues: 13, 17, 19, 23, 29, ...
Starting with the number 4, applying the rule of multiplying by 2 and then subtracting 3 gives the following sequence: 4, 5, 7, 11, 19, 35. This pattern can be calculated as follows: 4 x 2 - 3 = 5, 5 x 2 - 3 = 7, 7 x 2 - 3 = 11, 11 x 2 - 3 = 19, 19 x 2 - 3 = 35.
It is: (7+3)*(11-5) = 60