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Three parallel vertical lines. A bit like triangle ABC | triangle DEF, except that the lines are closer together.
If the sides AB, BC and CA of triangle ABC correspond to the sides DE, EF and FD of triangle DEF, then the two triangles are congruent if:AB = DE, BC = EF and CA = FD (SSS)AB = DE, BC = EF and angle ABC = angle DEF (SAS)AB = DE, angle ABC = angle DEF, angle BCA = angle EFD (ASA)If the triangles are right angled at A and D so that BC and EF are hypotenuses, then the triangles are congruent ifBC = EF and AB = DE (RHS)BC = EF and angle ABC = angle DEF (RHA).
This appears to be a comparison of two similar triangles. Measure the length of a corresponding side of each triangle. Let the side having the shorter length be b, and c the side having the longer length. Then the scale is b : c or b/c If possible multiply or divide the numbers forming the ratio to provide an answer in its lowest terms.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. There is, therefore, no visible symbol between ABC and DEF (<, =, >, ≠ etc). Furthermore, there is no information as to whether ABC is an angle, a triangle, an arc.
Triangle ABC is simlar to Triangle DEF. AB divided by DE equals x. BC divided by EF also equals x. CA divided by FA also equals x. Note: It only works like this. When two similar or congruent triangles are named (eg Triangle ABC), the order of the capital letters is important.