I think that you're doing the same thing that I did for IB. Here's what I think you're asking for :
0, 2, 6, 12, 20, 30, 42...
c₁ = 0
c₂ = 2
c₃ = 6 (c₂ + 4 = 2 + 4 = 6)
c₄ = 12 (c₃ + 6 = 2 + 4 + 6 = 12)
c₅ = 20 (c₄ + 8 = 2 + 4 + 6 + 8 = 20)
c₆ = 2 + 4 + 6 + 8 + 10
etc...
dn = (n/2) <2c₁ + (n-1) 2>
dn = (n/2) <2 (2) + (n-1) 2>
dn = (n/2) (4 + 2n - 2)
dn = (n/2) (2 + 2n)
dn = (2n/2) + (2n²/2)
dn = n + n²
i did
A surd is an irrational number that can't be expressed as a fraction as for example the square root of 2
Yes the square root of 2 is a surd which is an irrational number that can't be expressed as a fraction.
It is impossible to have a surd that is not irrational. Surds are defined to be an irrational number (square root of a number).
Yes.
Infinite surd is a term used in mathematics. The definition of an infinite surd is a never ending irrational number with an exact value that would be left in square root form.
2
the same way you find chuck Norris
A surd in the form a√b cannot, in general, be simplified.
Yes it is a surd
If the value of the surd is positive, then it will be another surd. Otherwise it will be a complex number.
A surd is the square root of an integer (whole number), e.g. square root of 2 is a surd. Pi is not the square root of an integer so not a surd, just an irrational number
I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..
No. It is not a criminal or civil offence!
No.
i did
algebra