f'(x) = 1/tan(x) * sec^2(x) where * means multiply and ^ means to the power of.
= cot(x) * sec^2(x)
f''(x) = f'(cot(x)*sec^2(x) + cot(x)*f'[sec^2(x)]
= -csc^2(x)*sec^2(x) + cot(x)*2tan(x)sec^2(x)
= sec^2(x) [cot(x)-csc^2(x)] +2tan(x)cot(x)
= sec^2(x) [cot(x)-csc^2(x)] +2
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The Geometrical meaning of the second derivative is the curvature of the function. If the function has zero second derivative it is straight or flat.
The first derivative is the rate of change, and the second derivative is the rate of change of the rate of change.
well, the second derivative is the derivative of the first derivative. so, the 2nd derivative of a function's indefinite integral is the derivative of the derivative of the function's indefinite integral. the derivative of a function's indefinite integral is the function, so the 2nd derivative of a function's indefinite integral is the derivative of the function.
Yes.
No. A quadratic equation always has a second derivative that is a constant. For example -3x2 + 10x - 2 first derivative -6x + 10 second derivative -6