172.16.0.0/16 gives you 65534 possible hosts within 1 subnet.
By binary math, you would need to increase the subnet mask to divide the network into subnets.
Think of the additional subnet mask bits as a binary value.
With 0 extra bits in the masks, you have 1 subnet.
With 1 bit, you have 2.
With 2 bits, you have 4.
With 3 bits, you have 8.
With 4 bits, you have 16.
We need 8, so we should add 3 bits to the subnet mask.
This would be a base CIDR of 172.16.0.0/19.
Since there are 256 possibilities in the 3rd octet (Based on Class B network), divide by 8. The resultant number is the increment value for each network address.
256 / 8 = 32.
Therefore, your networks would be:
172.16.0.0/19
172.16.32.0/19
172.16.64.0/19
172.16.96.0/19
172.16.128.0/19
172.16.160.0/19
172.16.192.0/19
172.16.224.0/19
With maximum (65536 / 8 - 2) 8190 hosts per subnet.
Additional:
Since we have 19 network bits, there are 13 bits remaining for hosts (total, as always 32). An all 0 string of host bits would leave you with your base network number
ex>
172.16.0.0/19 , host with all 0's
10101100.00010000.00000000.00000000
The resultant would be 172.16.0.0, which is your network address. Conversely, having a host with all 1's:
10101100.00010000.00011111.11111111
This would result in 172.16.31.255, which is the broadcast address for the first subnet.
These aren't usable as assignable addresses, but are used for network and broadcast purposes.
Using all of the 3 borrowed bits in a 111 situation gives you a resultant of 172.16.224.0/19, which is a legitimate network address. Network bits in this case carry over from the /16, and are simply added on. An IP address of 172.16.255.255 would be the broadcast address for the final subnet.
ex>
10101100.00010000.11111111.11111111
If you were doing a class A network, this wouldn't be as applicable. If all 3 of the first bits of a network address are 1, this puts your IP into a class D (224.0.0.0/4) subnet which is reserved for multicasting. This is only applicable to the first bits of the network address (starting from the very beginning).
Hope this helped at least a little.
The first four addresses in the 192.168.1.64 subnet, assuming a typical subnet mask of 255.255.255.0 (or /24), are 192.168.1.1, 192.168.1.2, 192.168.1.3, and 192.168.1.4. These addresses are usable for devices within that subnet. The address 192.168.1.64 itself typically represents the network address for that subnet and is not a usable host address.
The default subnet mask for the IP address 191.249.234.191 is 255.255.255.0. This is because the address belongs to Class B, which typically uses a default subnet mask of 255.255.0.0. However, if it's using CIDR notation for subnetting, it may also commonly be configured with a mask of 255.255.255.0 for more specific network segmentation.
Yes, the IP subnet 88.33.0.0 with a mask of 255.255.128.0 overlaps with the subnet 88.33.89.0 with the same mask. The subnet mask 255.255.128.0 indicates that the first 17 bits are the network part, meaning subnets can range from 88.33.0.0 to 88.33.127.255. Since 88.33.89.0 falls within this range, the two subnets indeed overlap.
This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.
To create ten networks from the 192.168.50.0 subnet, you need to determine how many bits to borrow from the host portion. Since 2^n must be at least 10 to accommodate the networks, you need to borrow 4 bits (since 2^4 = 16, which covers the requirement). This means the new subnet mask will be /28 (or 255.255.255.240), allowing for 16 subnets with 14 usable hosts each.
A Subnet calculator is used for determining the attributes of an IP subnet including the start of it. Results of the subnet calculation include the access control lists, the subnet range and the subnet bitmap.
No. 192.168.12.1 - 192.168.12.254 is one subnet (assuming 255.255.255.0 subnet mask)
If you divide a net into several subnets, subnet-zero is the first subnet. Some older technologies don't allow the use of this first subnet.If you divide a net into several subnets, subnet-zero is the first subnet. Some older technologies don't allow the use of this first subnet.If you divide a net into several subnets, subnet-zero is the first subnet. Some older technologies don't allow the use of this first subnet.If you divide a net into several subnets, subnet-zero is the first subnet. Some older technologies don't allow the use of this first subnet.
datagram subnet is connection oriented network.
It does not require a subnet mask.
The default subnet would be 255.0.0.0 (class A)
Moving a subnet to left to save bits is known as a supernet.
No, all subnets must use the same subnet mask
You would also have to know the subnet mask.You would also have to know the subnet mask.You would also have to know the subnet mask.You would also have to know the subnet mask.
If this is a default subnet mask, then it would be a class C subnet mask. If you are subnetting a network and this is not the default subnet mask, then it could be either a class A or class B.
Depends on how you subnet it.
The default subnet mask has a standard size. The custom subnet mask allows you to make subnets that are smaller or larger than the default.