The secret to working out your 11 times tables from 10 to 99 is this:
Separate the number like this:
11x45=495 4 5
Add the numbers together 11x45=495 4+5=9
Put the added number in between the first ones
495
And theirs your answer!
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Assuming the question is: 155 = 165 * 0.99x 155/165 = 0.99x log(155/165) = x*log(0.99) so x = log(155/165) / log(0.99) = -0.0272/-0.0044 = 6.2207 (approx).
f'(x)= 99x^2 - 500x + 700 Remember: if f(x)=ax^b where a and b are constants, then f'(x)=[bax^(b-1)]/b
x=0.(repeating)27 100x=27.(repeating)27 100x−x=27.(repeating)27− 0.(repeating)27/99x=27x=27/99=3/11
Assuming the .363636 is a repeating decimal... First, assign x = 41.363636363636... Then, 100x = 4136.36363636... Subtract the first line from the second to cancel out the repeating part: 99x = 4095 x = 4095/99 = 455/11, or 41 4/11
let the number 3.14 be equal to 'x' now 10x=31.41414141414141 100x=314.141414141414 now 100x-x=314.14141414 - 3.14141414 99x=311 x=311/99