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There are infinitely many rules. It is easy to find a polynomial of order 5 (or higher) such that the first five numbers are as listed in the question followed by any number that you wish. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest polynomial of order 4 is:
T(n) = (n^4 - 6n^3 + 15n^2 - 10n + 4)/4 for n = 1, 2, 3, ...
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What number comes next in the sequence 26 51 95?
158 One possible sequence is t(n) = 0.5*(19n2 - 7n + 40) for n = 1, 2, 3, ...
Is 51 and 57 prime numbers?
No. Neither one are. 51 = 17 x 3 57 = 19 x 3
Why 57 51 are not prime numbers?
57 can be divided by 3 and 19 with no remainder. 51 can be divided by 3 and 17 with no remainder.
What times what equels 51?
It can be: 3*17 = 51 or 1*51 = 51
What times equal 51?
1 x 51, 3 x 17, 17 x 3, 51 x 1
