It is s units on some unspecified scale for measuring length.
To find the side length of a square with an area of 3 square units, you can use the formula for the area of a square, which is ( A = s^2 ), where ( s ) is the side length. To find the side length, take the square root of the area: ( s = \sqrt{3} ). Therefore, the side length is approximately 1.73 units.
The area ( A ) of a square can be represented as a function of its side length ( s ) using the equation ( A(s) = s^2 ). In this equation, ( A ) is the area, and ( s ) is the length of one side of the square. As the side length increases, the area increases quadratically.
The area of a square is given by the formula ( A = s^2 ), where ( s ) is the side length. If the smaller square has an area ( A^2 ), its side length is ( s = A ). When enlarged to an area of ( 25A^2 ), the new side length is ( s' = \sqrt{25A^2} = 5A ). Thus, the side of the smaller square was increased from ( A ) to ( 5A ), which is a fivefold increase.
If the side of the square is of length s then the perimeter is 4*s.
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
The formula for the area of a square is: s * s where s = length of a side The formula for the perimeter of a square is: 4 * s where s = length of a side
The area ( A ) of a square can be represented as a function of its side length ( s ) using the equation ( A(s) = s^2 ). In this equation, ( A ) is the area, and ( s ) is the length of one side of the square. As the side length increases, the area increases quadratically.
Since a square has sides of equal length the area is the length of one side squared. You can find the length of one side by taking the square root of the area of the square. The length of one side is approximately 2.93. Then you plug in the length of the side into the perimeter formula. P = S+S+S+S P = 2.93+2.93+2.93+2.93 P = 11.72
It's the square of the length of a side. If the length of a side is L, then the area of the square is L2, or L * L.
The area of a square is S2 where S is the length of one side. So the length of the side of the square is the SQROOT(AREA) or SQROOT(144cm2), which is 12 cm
The area of a square is given by the formula ( A = s^2 ), where ( s ) is the side length. If the smaller square has an area ( A^2 ), its side length is ( s = A ). When enlarged to an area of ( 25A^2 ), the new side length is ( s' = \sqrt{25A^2} = 5A ). Thus, the side of the smaller square was increased from ( A ) to ( 5A ), which is a fivefold increase.
If the side of the square is of length s then the perimeter is 4*s.
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
The formula for the area of a square is ( A = s^2 ), where ( s ) represents the length of one side of the square. To find the area, simply square the length of a side. For example, if the side length is 4 units, the area would be ( 4^2 = 16 ) square units.
The side length is 6. For a square A = s2 and s = sqrt (A)
Oh honey, it's not rocket science. The perimeter of a square is just the sum of all its sides. So for a square with side length 's', you just add 's' four times to get the perimeter. Easy peasy lemon squeezy!
First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.