Three of them
I Believe it would be 2.32 x 106.
2 of them.
Addition:Convert the numbers so that the exponents are the same. Add the coefficients. Move the decimal point if necessary.3.5 x 106 + 5.1 x 104 = 3.5 x 106 + 0.051 x 106 = 3.6 x 106 (rounded to two significant figures)Subtraction:Same as addition, except subtract instead of adding.4.5 x 109 - 7.8 x 1011 = 0.045 x 1011 - 7.8 x 1011 = -7.8 x 1011 (rounded to two significant figures)**Notice that if you change the smaller exponent to the larger exponent, you won't have to change exponents at the end.Multiplication:Multiply coefficients and add exponents.(5.9 x 1025)(1.2 x 106) = 7.1 x 1031 (rounded to two significant figures)Division:Divide coefficients and subtract the exponent in denominator from the exponent in the numerator.(1.59 x 1015)/(8.74 x 1022) = 0.182 x 10-7 = 1.82 x 10-8 (rounded to three significant figures)
1.000230 x 106 The tailing zero preserves itself as a significant digit. If it isn't significant, leave it off.
Three of them
To 1 significant figure, it would be 8 x 10^3.
I Believe it would be 2.32 x 106.
3 of them.
2 of them.
Addition:Convert the numbers so that the exponents are the same. Add the coefficients. Move the decimal point if necessary.3.5 x 106 + 5.1 x 104 = 3.5 x 106 + 0.051 x 106 = 3.6 x 106 (rounded to two significant figures)Subtraction:Same as addition, except subtract instead of adding.4.5 x 109 - 7.8 x 1011 = 0.045 x 1011 - 7.8 x 1011 = -7.8 x 1011 (rounded to two significant figures)**Notice that if you change the smaller exponent to the larger exponent, you won't have to change exponents at the end.Multiplication:Multiply coefficients and add exponents.(5.9 x 1025)(1.2 x 106) = 7.1 x 1031 (rounded to two significant figures)Division:Divide coefficients and subtract the exponent in denominator from the exponent in the numerator.(1.59 x 1015)/(8.74 x 1022) = 0.182 x 10-7 = 1.82 x 10-8 (rounded to three significant figures)
1.000230 x 106 The tailing zero preserves itself as a significant digit. If it isn't significant, leave it off.
2.7 X 106 ======= Zeros are superfluous unless needed for significant figures.
615 times 38 is 23,370β¬ rounding off to one significant figure it is 20,000
(9 X 10-2) X (9 X 106) = 8 X 105, to the justified number of significant digits.
The number 27000000 expressed using 1 significant figure is 3 x 10^7.
Three.