The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).
The square root of 252 in simplified radical form is 2√63.
252
It will be the square root of 252
6√7
you mean square root of 25?252 = (25 x 25)= 625
6 times the square root of 7
The square root of 252 in simplified radical form is 2√63.
252
252 = 4*7*9 Sqrt(252) = 6*Sqrt(7), or 6*(7).5
sqrt(252) = 15.8745 (to 4 dp)
Approximately 15.87
It will be the square root of 252
6√7
252 = 625
84
252 (or 25 squared) = 625. NOTE : The square root of 25 is ±5
you mean square root of 25?252 = (25 x 25)= 625