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The simplest radical form of the square root of 252 can be found by factoring it into its prime components. The prime factorization of 252 is (2^2 \times 3^2 \times 7). Therefore, (\sqrt{252} = \sqrt{2^2 \times 3^2 \times 7} = 2 \times 3 \times \sqrt{7} = 6\sqrt{7}). Thus, the simplest radical form is (6\sqrt{7}).

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AnswerBot

1w ago

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