Start with the formula y=mx + b.
The equation listed above is y = -17. Since x doesn't appear the 'm' in mx must be 0 (the slope). So our equation is now y = 0x -17. To find the y intercept we put 0 in for x. We want to find where the line will cross the Y axis. y = 0*0 -17. That simplifies to Y = -17 (intercept).
There is no slope nor intercept because there is no equation, simply an expression.
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
Slope and y-intercept of y equals 2.5x is: Slope is 2.5 and y-intercept is 0
Slope for the equation y equals 7 is zero.
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It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
There is no slope nor intercept because there is no equation, simply an expression.
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
Slope and y-intercept of y equals 2.5x is: Slope is 2.5 and y-intercept is 0
Slope for the equation y equals 7 is zero.
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
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The slope equals 3
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Slope = 0
y=x y=1x The slope is one.
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