The y intercept is 3, and since your slope is 0, you have a horizontal line.
Slope = 0, intercept = 3
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
y = 5x - 3
the slope is -3 and the y-intercept is (0,4)
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.
Slope = 0, intercept = 3
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3
4y = 3xDivide each side by 4:y = (3/4) xThe slope of the graph is (3/4).The y-intercept is zero. (The line goes through the origin.)
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
y = 5x - 3
If you mean: y = -3x then the slope is -3 and there is no y intercept
-11
slope: -3 y-intercept: 9
the slope is -3 and the y-intercept is (0,4)
3
The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.