To find the slope between the points (-1, -3) and (-22, y), we need the y-coordinate of the second point. However, the slope formula is given by ( m = \frac{y_2 - y_1}{x_2 - x_1} ). If we assume the second point is (-22, -22), the slope would be calculated as ( m = \frac{-22 - (-3)}{-22 - (-1)} = \frac{-22 + 3}{-22 + 1} = \frac{-19}{-21} ), simplifying to (\frac{19}{21}). Without the y-coordinate of the second point, the slope cannot be determined.
To find the slope between the points (22) and (4, -3), we first need to clarify the points. Assuming the points are (22, y1) and (4, -3), where y1 can be any value, we use the slope formula ( m = \frac{y2 - y1}{x2 - x1} ). If we set y1 to 0 for simplicity, the calculation becomes ( m = \frac{-3 - 0}{4 - 22} = \frac{-3}{-18} = \frac{1}{6} ). Thus, the slope between these two points is ( \frac{1}{6} ).
if the slope is 1 in 22, draw horizontal line 22 long, then vertical line 1 high, hypotonuse is slope, angle of slope is (INV tan ( 1 / 22)) . same deal for 1 in 66, 66 along then 1 up, angle is (INV tan ( 1 / 66))
Points: )1, 1) and (3, 3) Slope: 1
If you mean points of (3, 3) and (-3, -1) then the slope works out as 2/3
Slope = (1 - 4)/(3 - 1) = -3/2 = -1.5
The slope is -1/2.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (4, 3) and (2, 2) Slope: 1/2
five is the slope.
if the slope is 1 in 22, draw horizontal line 22 long, then vertical line 1 high, hypotonuse is slope, angle of slope is (INV tan ( 1 / 22)) . same deal for 1 in 66, 66 along then 1 up, angle is (INV tan ( 1 / 66))
Points: )1, 1) and (3, 3) Slope: 1
A slope of -3 is steeper.
If you mean points of (1, 5) and (-1, -1) then the slope works out as 3
The slope of two lines are perpendicular only if their slopes multiplied together equal -1 (m1*m2 = -1). So if a line has a slope of -3 then a line perpendicular to this one has a slope of -1/-3 or 1/3.
Points: (1, -3) and (2, -5) Slope: -2
If you mean points of (3, 3) and (-3, -1) then the slope works out as 2/3
Slope = (1 - 4)/(3 - 1) = -3/2 = -1.5