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What is the slope of a line perpendicular to the line 5x - 15y 20?
To find the slope of a line perpendicular to the given line, we first need to determine the slope of the line represented by the equation (5x - 15y = 20). Rearranging it into slope-intercept form (y = mx + b), we get (y = \frac{1}{3}x - \frac{4}{3}), which shows that the slope (m) is (\frac{1}{3}). The slope of a line perpendicular to this line is the negative reciprocal, which is (-3).
Are the lines y equals negative x minus 4 and 5x plus 5y equals 20 perpendicular explain your answer?
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
What is the slope of a line if the variables are 30 10 and 20 20?
The slope is -1. (30, 10) and (20, 20) are both (x, y) coordinates, and can both be plotted on a 2-D graph. For every point that you go forward, you also have to go 1 point down to meet both points.
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
How do you graph y equals 1.35x-31.25?
32.6
What is the slope of a line perpendicular to the line 5x - 15y 20?
To find the slope of a line perpendicular to the given line, we first need to determine the slope of the line represented by the equation (5x - 15y = 20). Rearranging it into slope-intercept form (y = mx + b), we get (y = \frac{1}{3}x - \frac{4}{3}), which shows that the slope (m) is (\frac{1}{3}). The slope of a line perpendicular to this line is the negative reciprocal, which is (-3).
What is the slope of this equation y equals 20-3X?
23
What is the slope of -18-7 -20-9 on a graph?
Points: (-18, -7) and (-20-9) Slope works out as 1
Are the lines y equals negative x minus 4 and 5x plus 5y equals 20 perpendicular explain your answer?
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
What is the slope of a line if the variables are 30 10 and 20 20?
The slope is -1. (30, 10) and (20, 20) are both (x, y) coordinates, and can both be plotted on a 2-D graph. For every point that you go forward, you also have to go 1 point down to meet both points.
What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
What is the slope of the line that passes through the points 14 5 and 20 4?
Points: (14, 5) and (20, 4) Slope: -1/6
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
How would the slope of a savings graph change if you saved 40 per month instead of 20?
The slope or gradient of a line that represented the change in savings over time would increase (in this case it would double). This is because in the example in your question, you would be saving twice as much money per unit time. As such the gradient of the line would change from 20 (20 / 1) to 40 (40 / 1).
Find the slope parallel to x y 20?
Parallel lines have the same slope. So if you have y=x+20 for example, the slope is 1 and any parallel line has slope 1 also. I think your equation is x=y+20 but since the+ and - don't show up i am not sure If it is we can rewrite it as -y=-x+20 or y=x-20 and slope is still 1 so any parallel line has slope 1.
What is the perpendicular distance from the point 2 4 to the straight line y equals 2x plus 10?
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
What is a slope of the line that passes through-20,-4 and -12,-10?
I believe the slope would be: -4 / 3
