To find the slope of a line perpendicular to another line, we first need to determine the slope of the original line. The given equation can be rearranged into the slope-intercept form (y = mx + b). Rearranging (2y = 3x + 1) gives (y = \frac{3}{2}x + \frac{1}{2}), so the slope of the original line is (\frac{3}{2}). The slope of a line perpendicular to it is the negative reciprocal, which is (-\frac{2}{3}).
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
- 1/3
It is -1/2
Without an equality sign it can't be considered to be an equation but in general if the slope was 3 then the perpendicular would be -1/3
12
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
If you mean y = 2x+5 then the perpendicular slope is -1/2
It is: -1/2
-5
Slope of a line = m slope of perpendicular line = -1/m
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
It is -1/2
- 1/3
Without an equality sign it can't be considered to be an equation but in general if the slope was 3 then the perpendicular would be -1/3