Y=X+4 or
Y=(1)X+4
is of the form Y=mX+b, where m is the slope and bis the y-intercept.
Therefore the slope of the line described by that equation is 1.
The slope of the line that represents the graph of that equation is 15.
-4
1
If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
The general equation of a line is: y = mx + b where m is the slope and b is the y-intercept. 3x + y = 4 y = -3x + 4 The slope is -3.
The slope of the line that represents the graph of that equation is 15.
-4
1
Parallel, the slope of the second equation is 4
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
The general equation of a line is: y = mx + b where m is the slope and b is the y-intercept. 3x + y = 4 y = -3x + 4 The slope is -3.
Slope = 4
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
- 1/3
y=-(8/7)x+4 Therefore, the slope= -(8/7)
The equation for the line is y = mx +b the slope is the value of m For example if y = 3x +4 the that is the equation that completely defines the line; its slope is 3