Q: What is the slope of the line -3 4 and 3 0?

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Points: (3, -2) and (0, 4) Slope: -2

Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2

3/7

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3

If you mean points of (0, 4) and (4, -2) then the slope is -3/2

Related questions

Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2

Points: (3, -2) and (0, 4) Slope: -2

The slope of the line joining the two pints is (4 - 2)/(-3 - 0) = -2/3 Therefore the slope of the perpendicular is 3/2

A pair of points doesn't have a slope. But the line between them does.The line between (0, 3) and (8, -4) has a slope of -7/8 = -0.875 .

Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2

Points: (3, 4) and (5, 4) Slope: (4-4)/(3-5) = 0 There is no slope and it is a straight line parallel to the x axis

3/7

If the points are: (0, 3) and (8, -3) then the slope works out as -3/4

From the given points the slope of the line works out as 3/4

Points: (-3, -3) and (4, -3) Slope: (-3--3)/(-3-4) = 0

Points: (3, 5) and (4, 5) Slope: 0

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3