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36x-9y=15 36x-15=9y y=4x-15/4 remember slope is the m on y=mx+b so slope=4
The slope of the line that represents the graph of that equation is 15.
The slope is 1/3 and the y-intercept is -1.
It is 3x + 5y = 155 The slope of the line 5x -3y = 9: 5x - 3y = 9 → 3y = 5x - 9 → y = 5/3 x - 3 → slope is 5/3 → slope of perpendicular line is -3/5 Intercept at x = 15 → y = 5/3 x 15 - 3 = 22 → equation of perpendicular line is: y - 22 = -3/5 (x - 15) → 5y - 110 = -3x + 45 → 3x + 5y = 155
I'm assuming here that this line is a straight line. If so, it has the general equation y=mx+c (where m= the gradient/slope and c is the intercept). Substituting in the values provided in the question, we yield; 15= (9x9)+c We then solve and rearrange; 15=81+c 15-81=c -66=c. Therefore, the slope intercept is -66