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The slope is -1.25

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10y ago

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How do you find the equation of a line that has a x intercept of 5 and a slope of 4?

I assume you mean the slope-intercept formula, y=mx+b First, put it in point-slope form. that is y-0=4(x-5) the 4 is the slope, and the 0 and five are from the x-intercept y-0=4(x-5) simplifies to y=4x-20, which is the equation you wanted


What is the equation of the line that has a slope of 4 5 and a y-intercept of -1?

The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of ( \frac{4}{5} ) and a y-intercept of -1, the equation of the line is ( y = \frac{4}{5}x - 1 ).


The slope of the line is two fifths and the y intercept is 4 What is the slope intercept equation of the line?

y = mx + b where m = slope and b = y intercept y = 2/5 x + 4


What is the equation in slope-intercept form of the line that has a slope of -3 and contains the point 4 and -5?

It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form


What is the slope and y intercept for y equals -x plus 5?

slope = -1y-intercept = 5


What is the slope intercept form for x-y5?

If you mean x-y = 5 then y = x-5 whereas it has a slope of 1 and a y intercept of -5


Write the equation in slope intercept form of the line that has a slope of -3 and contains the point 4 5?

y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form


Write the equation in slope intercept form of the line that has a slope of -3 and contains the point 4 -5?

y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form


What is the slope and y-intercept for X-4y equals 5?

x-4y = 5 -4y = -x+5 y = 0.25x-1.25 which is now in slope intercept form


What is the slope and y-intercept and x-intercept of y equals 5x plus 10?

Slope is 5 or 5/1 which ever floats your boat y-intercept is 10 x-intercept is -2


Slope is -8 y intercept is 5 what is y?

y = slope*x + intercept, so y = -8x + 5


What is the intercept of a line that has a slope of 3 and passes through point (5 4)?

To find the intercept of a line with a slope of 3 that passes through the point (5, 4), we can use the point-slope form of the line equation: (y - y_1 = m(x - x_1)). Substituting the slope (m = 3) and the point (x₁ = 5, y₁ = 4), we get (y - 4 = 3(x - 5)). Simplifying this gives us the equation (y = 3x - 11), indicating that the y-intercept is -11.