The slope is -1.25
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of ( \frac{4}{5} ) and a y-intercept of -1, the equation of the line is ( y = \frac{4}{5}x - 1 ).
y = mx + b where m = slope and b = y intercept y = 2/5 x + 4
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form
slope = -1y-intercept = 5
If you mean x-y = 5 then y = x-5 whereas it has a slope of 1 and a y intercept of -5
I assume you mean the slope-intercept formula, y=mx+b First, put it in point-slope form. that is y-0=4(x-5) the 4 is the slope, and the 0 and five are from the x-intercept y-0=4(x-5) simplifies to y=4x-20, which is the equation you wanted
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of ( \frac{4}{5} ) and a y-intercept of -1, the equation of the line is ( y = \frac{4}{5}x - 1 ).
y = mx + b where m = slope and b = y intercept y = 2/5 x + 4
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form
slope = -1y-intercept = 5
If you mean x-y = 5 then y = x-5 whereas it has a slope of 1 and a y intercept of -5
y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form
y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form
x-4y = 5 -4y = -x+5 y = 0.25x-1.25 which is now in slope intercept form
Slope is 5 or 5/1 which ever floats your boat y-intercept is 10 x-intercept is -2
y = slope*x + intercept, so y = -8x + 5
To find the intercept of a line with a slope of 3 that passes through the point (5, 4), we can use the point-slope form of the line equation: (y - y_1 = m(x - x_1)). Substituting the slope (m = 3) and the point (x₁ = 5, y₁ = 4), we get (y - 4 = 3(x - 5)). Simplifying this gives us the equation (y = 3x - 11), indicating that the y-intercept is -11.