What is the slope to 3x-4y-16 equals 0?

Answer 1

3x - 4y -16 = 0

Algebraically rearrange to to make '4y' the subject.

Hence

4y = 3x - 16 ( Note the change of sign, on taking the '4y' across the equals to replace the zero. ).

Divide both sides by ;4;

y = (3/4)x - 16/4

y = ( 3/4)x - 4

Hence the slope is ' 3/4 ' and the y-intersect is '-4'.

NB For all straight line of the form y = mx + c

'm' is the slope , and 'c' is the y-intersect.

All you need to do on being given linear equations of the form

px + ny + c = o

or

px + c = ny

or

px + ny = c

etc. is to algebraically rearrange into the form of y = mx + c , making sure you change the signs correctly, and then dividing both sides by the coefficient of 'y' .

Answer 2

If: 3x-4y-16 = 0

Then: -4y = -3x+16

And: y = 0.75x-4 which is now in slope-intercept form

So the slope is 3/4 or 0.75