If: 3x+4y = 4
Then: y = -3/4x+1 and so the slope is -3/4 or -0.75 with a y intercept of 1
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
3x+4y = 4 4y = -3x+4 y = -3/4x+1 So the slope is -3/4 and the intercept is 1
3x + 4y = 12 Subtract 3x from each side 4y = 12 - 3x Divide by 4 on each side y = 3 - .75x The slope is what is multiplied by "x" or -.75
3x+4y = 8 4y = -3x+8 y = -3/4x+2 in slope intercrpt form It has a negative slope so the straight line goes 'downhill'
0.75
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
3x+4y = 4 4y = -3x+4 y = -3/4x+1 So the slope is -3/4 and the intercept is 1
3x + 4y = 12 Subtract 3x from each side 4y = 12 - 3x Divide by 4 on each side y = 3 - .75x The slope is what is multiplied by "x" or -.75
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
3x+4y = 8 4y = -3x+8 y = -3/4x+2 in slope intercrpt form It has a negative slope so the straight line goes 'downhill'
0.75
q2
3x - 4y -16 = 0 Algebraically rearrange to to make '4y' the subject. Hence 4y = 3x - 16 ( Note the change of sign, on taking the '4y' across the equals to replace the zero. ). Divide both sides by ;4; y = (3/4)x - 16/4 y = ( 3/4)x - 4 Hence the slope is ' 3/4 ' and the y-intersect is '-4'. NB For all straight line of the form y = mx + c 'm' is the slope , and 'c' is the y-intersect. All you need to do on being given linear equations of the form px + ny + c = o or px + c = ny or px + ny = c etc. is to algebraically rearrange into the form of y = mx + c , making sure you change the signs correctly, and then dividing both sides by the coefficient of 'y' .
-3X + 4Y = -4 get equation in form y = mx +b m = slope b = intercept 4Y = 3X-4 Y = 3/4 X - 1 m = 3/4 b = -1
y=-3/4x+4/3
3/4
-3/4 if the question is 3x+4y