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You need to carry out the division. If the remainder is 0 then it is divisible, if not it is not. There are divisibility rules which can help with small or simple divisors but these are quite limited.
The smallest multiple of a natural number n, is 1xn, or the number itself. We do not count 0xn which of course would be zero for every natural number n.
It's redundant. The LCM of two natural numbers is the smallest integer solution. It's the smallest positive integer that all the members of a given set of numbers will divide into evenly with no remainder.
Prime numbers. They are divisible evenly (no remainder) by one and themselves only.
Your question doesn't make sense, I'm sorry. Integer means a natural number like 2 or 10 or 1047893671282 or even -1048278163.
2520 is the smallest multiple of of first ten natural numbers.
If it needs to be natural it is one.
You need to carry out the division. If the remainder is 0 then it is divisible, if not it is not. There are divisibility rules which can help with small or simple divisors but these are quite limited.
The smallest multiple of a natural number n, is 1xn, or the number itself. We do not count 0xn which of course would be zero for every natural number n.
No, 7 is a natural number divisible by 7 and not 14 for example. In fact every odd multiple of 7 (i.e. 7 times 1,3,5,7,...) is divisible by 7 and not 14.
72
11
It's redundant. The LCM of two natural numbers is the smallest integer solution. It's the smallest positive integer that all the members of a given set of numbers will divide into evenly with no remainder.
Prime numbers. They are divisible evenly (no remainder) by one and themselves only.
That would be 28 itself, since 28 is a multiple of 7.
1 is the smallest natural number.
2520. The number needs to have a prime factorization of 23*32*5*7=2520.