The required number is 90. The values produced by dividing 90 by 2, 3, 5, 7, and 11, the five smallest prime numbers, do not satisfy all the requirements: 90/2 = 45, which is not evenly divisible by 2; 90/3 = 30, which is not evenly divisible by 9; 90/5 = 18, which is not evenly divisible by 5; and the quotient of 90 and either 7 or 11 is not an integer itself.
Any whole number can be divided by 1 without leaving a remainder.
Any number. Can be divided by 1 without remainder.
49 can be divided by these numbers without leaving a remainder: 1 7 and 49.
It is 30.
When a number can be divided by another number without leaving a remainder, it is called divisible. For example, 10 is divisible by 2 because when we divide 10 by 2, there is no remainder.
12
46 can be divided by these numbers without leaving a remainder: 1 2 23 and 46.
Any whole number can be divided by 1 without leaving a remainder.
1 can be divided into both numbers with no remainder
Any number. Can be divided by 1 without remainder.
49 can be divided by these numbers without leaving a remainder: 1 7 and 49.
Any multiple of that number can be.
24
It is 30.
0.4286
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
The smallest number that can be divided by 2, 3, and 4 without leaving a remainder is the least common multiple (LCM) of these numbers. To find the LCM, we need to identify the prime factors of each number. The prime factors of 2 are 2, 3 is 3, and 4 is 2 x 2. The LCM is the product of the highest power of each prime factor that appears in any of the numbers, so the LCM of 2, 3, and 4 is 2 x 2 x 3 = 12. Therefore, the smallest number that can be divided by 2, 3, and 4 without leaving a remainder is 12.