What you have to do here is find the least common multiple of 46 and 8, then add 3.
Try 27
5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.
Yes Example: 1234567 divided by 1000 has a remainder of 567.
No prime number can be divided by 4 exactly.
787409579-475490949-8498902757209
Try 27
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5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.
17
One possibility is 138.
Yes Example: 1234567 divided by 1000 has a remainder of 567.
No prime number can be divided by 4 exactly.
300
787409579-475490949-8498902757209
You take 3x7+4=25 :)
To find the least three-digit dividend that gives a remainder of 4 when divided by 40, we can start with the smallest three-digit number, which is 100. We want to find a number ( x ) such that ( x \equiv 4 \mod 40 ). The smallest three-digit number that meets this condition is 104, because ( 104 - 4 = 100 ) is divisible by 40. Thus, the least three-digit dividend is 104.
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