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What is the smallest possible value of 20P plus 10Q plus R when P and Q and R are different positive integers?
To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.
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