To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.
12
To find positive integers that sum to 14 and have the smallest product, we can use the fact that the product of numbers is minimized when the numbers are as far apart as possible. The optimal way to split 14 is into one integer of 1 and the other of 13, resulting in the integers 1 and 13. The product of these two integers is (1 \times 13 = 13), which is the smallest possible product for integers that sum to 14.
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
The positive integers are {1, 2, 3, 4, 5, ...}. The smallest one is 1.
1 and 13.
Among positive integers, 6
12
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
1,3,5,7
The positive integers are {1, 2, 3, 4, 5, ...}. The smallest one is 1.
For positive integers, 1 is.
The sum of the smallest 15 positive integers is 120. The sum of the smallest 15 negative integers is -120.
Of the positive integers, 4 is.
Among positive integers, 6
The smallest common factor of any set of positive integers is 1.
The smallest common factor of any set of positive integers is 1.