Q: What is the smallest whole number which 3 6 7 can divide and leave a remainder 1?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

361

24

yes

5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.

a number that can be divided and leave no remainder.

Related questions

361

24

28 is one such number.

Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).

30/21 = 1 with a remainder of 9

yes

3 can't divide into anything and leave a remainder of 28. If you divide 43 into 157, the answer is 3, with a remainder of 28.

5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.

a number that can be divided and leave no remainder.

Divide top number by bottom number leave remainder on top and move other number to sideex: x/c= a Rb Key: R=remainderThen, put your answer here:ex: ab/cPut your remainder here:ex: ab/c

There are positive integers which divide 2004 to leave a remainder of 24: 30, 33, 36, 44, 45, 55, 60, 66, 90, 99, 110, 132, 165, 180, 198, 220, 330, 396, 495, 660, 990, and 1980

It is LCM(3, 4, 5) + 2 = 62