Y=4, X=1
x=-2, y=2
The equation has infinitely many solutions.
x = -4y so 3x = -12y Substituting in the second equation, -12y + 2y = 20 or -10y = 20 ie y = -2 And then x = -4y implies that x = 8 Solution: x = 8, y = -2
-x + 4y = 8
No.
x=4y+1 x=4y-1 No,they have different solutions.
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
No.
Y=4, X=1
x=-2, y=2
The solution is:- x = 0 and y = 5
Add the two equations and get 4x = 12 so x = 3 and y = -1
The equation has infinitely many solutions.
Each of these have an infinite number of solutions. Never can they be equal.
3x=4y-x 4x=4y x=y
x = -4y so 3x = -12y Substituting in the second equation, -12y + 2y = 20 or -10y = 20 ie y = -2 And then x = -4y implies that x = 8 Solution: x = 8, y = -2