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Is The solution set of an equation of a circle is all the points that lie on the circle?
Yes, it is.
The solution set of an equation of a circle is all of the points that lie in the circle.?
The solution set of an equation of a circle includes all the points (x, y) that satisfy the equation, typically expressed in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is its radius. This set encompasses all points inside the circle, as well as those on its boundary. Therefore, it represents the entire area contained within and including the circumference of the circle.
Which point does not lie on the circle centered at A(3 1) and passing through the origin (0 0)?
Lots of points don't lie on the circle. In fact, there are (in a way) more points NOT on the circle, than points on the circle.
The solution set of an equation of a circle is all of the points that lie on a cirlce?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
The term for a portion of a circle between two points a and b that lie on the circle is?
An arc.
Is The solution set of an equation of a circle is all the points that lie on the circle?
Yes, it is.
The solution set of an equation of a circle is all of the points that lie in the circle.?
The solution set of an equation of a circle includes all the points (x, y) that satisfy the equation, typically expressed in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is its radius. This set encompasses all points inside the circle, as well as those on its boundary. Therefore, it represents the entire area contained within and including the circumference of the circle.
Which point does not lie on the circle centered at A(3 1) and passing through the origin (0 0)?
Lots of points don't lie on the circle. In fact, there are (in a way) more points NOT on the circle, than points on the circle.
The solution set of an equation of a circle is all of the points that lie on the circle?
the answer is false - apex
The solution set of an equation of a circle is all of the points that lie on a cirlce?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
Consists of the endpoints of a diameter of a circle and all points of the circle that lie on one side of the diameter starts with s?
Semicircle
Can noncollinear points lie on a circle?
Yes. In fact, given any three non-collinear points, there is one (and only one) circle that passes through all three points.
Definition of circular region of circle?
the set f all points of the plane which lie either on the circle or inside the circle form the circular region
What types of equations or inequalities describe points x y that lie on a circle?
Linear equations or inequalities describe points x y that lie on a circle.
The term for a portion of a circle between two points a and b that lie on the circle is?
An arc.
If six points lie on a circle how many quadrilaterals can be drawn joining these points?
5
A line segment that connects any two points of a circle is called?
A chord is a line which connects two points which lie on a circle.
