x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
3+3x+7x=13 3x+7x=10 10x=10 x=1
4x +13 = 93-6x. Adding 6x to each side gives: 10x+13 = 93. Subtracting 13 from each side gives: 10x = 80. Dividing both sides by 10 gives: x = 8.
3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3
10x + 13 = 17 ie 10x = 17 - 13 so x = 4/10 = 0.4
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
5x+8 = 10x+35x-10x = 3-8-5x = -5x = 1 and by substituting the value of x into the equations y = 13
3+3x+7x=13 3x+7x=10 10x=10 x=1
13 + 2x = 32x = 3 - 132x = -10x = -5
4x +13 = 93-6x. Adding 6x to each side gives: 10x+13 = 93. Subtracting 13 from each side gives: 10x = 80. Dividing both sides by 10 gives: x = 8.
3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
x = 3 and y = 2
2x plus 3y
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?