One equation with two unknowns usually does not have a solution.
IMPOSSIBLE
It is a cubic polynomial in x and its value depends on the value of x.
No.
x3 + 125 Use the sum of two cubes. (x+5)(x2-5x+25)
One equation with two unknowns usually does not have a solution.
IMPOSSIBLE
It is a cubic polynomial in x and its value depends on the value of x.
No.
y2=x3+3x2
No, it is not.
(xn+2-1)/(x2-1)
x3 + 125 Use the sum of two cubes. (x+5)(x2-5x+25)
X3 - 4 = 2 X3 = 6 X = 61/3 X = about 1.817
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
5