x - 9 is an expression, neither an equation not an inequality. An expression cannot have a solution.
To determine if ( x = 9 ) is a solution of the equation ( x + 6(x - 4) = 0 ), substitute ( 9 ) for ( x ): [ 9 + 6(9 - 4) = 9 + 6(5) = 9 + 30 = 39 \neq 0. ] Since the left side does not equal zero, ( x = 9 ) is not a solution of the equation.
x^2 +9 =x^2 -9 9=-9 No solution
The inequality ( x^2 > 81 ) can be solved by taking the square root of both sides. This gives ( x > 9 ) or ( x < -9 ). Therefore, the solution set is ( x < -9 ) or ( x > 9 ). In interval notation, this is expressed as ( (-\infty, -9) \cup (9, \infty) ).
The equation ( x^2 - 18x + 81 = 0 ) can be factored as ( (x - 9)^2 = 0 ). This means the only solution for ( x ) is ( x = 9 ). Thus, the equation has a double root at ( x = 9 ).
(x-9)(X+8)
x=9 is as simple as it gets. The question is the solution.
If you mean x+5y = 4 then (9, -1) is the solution
To determine if ( x = 9 ) is a solution of the equation ( x + 6(x - 4) = 0 ), substitute ( 9 ) for ( x ): [ 9 + 6(9 - 4) = 9 + 6(5) = 9 + 30 = 39 \neq 0. ] Since the left side does not equal zero, ( x = 9 ) is not a solution of the equation.
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x^2 +9 =x^2 -9 9=-9 No solution
Assuming you mean x=9-4, x=5
false, there is a solution -34x - 9 = 24 +9 +9 -34x = 33 x= - 33/34 or x = -.970588
X+9=17;8
Suppose x is the smaller number then x+9 is the larger. Then x*(x+9)= 162 or x2 + 9x - 162 = 0 or (x-9)*(x+18) = 0 So: x = 9 giving the solution 9 and 18 OR x = -18, giving the solution -18 and -9
To determine if ( x^2 - 9 ) is a solution or no solution, we need more context, such as an equation or inequality to solve. If you are asking if ( x^2 - 9 = 0 ) has solutions, then yes, it does, as it can be factored to ( (x - 3)(x + 3) = 0 ), giving solutions ( x = 3 ) and ( x = -3 ). If you're referring to something else, please provide additional details.
-79
If you mean x+4 = 13 then the value of x is 9