The area of that wall would be 138 square feet.
If a right angle triangle has been formed then: 24*cos(71) = 7.813635707 feet or about 7.8 feet is the height
9 yrds
great wall of china
The distance around the wall is 42 linear feet.
13
(a) each what covers 25 square foot?(b) what do you want to know?
The distance around the wall (perimeter) is 216 feet.
It could be a wall that is 1 square foot in cross section and 47 feet long.
If a right angle triangle has been formed then: 24*cos(71) = 7.813635707 feet or about 7.8 feet is the height
9 yrds
the exposed section is 187 feet long and 62 feet high.
2 feet from top
great wall of china
231ft x 9ft = 2079ft2
Okay, this requires a little simple math and some three dimensional thinking. For the fence (wall) planks alone, you will need 55 eight foot 2 x 4's. For a simple box frame you will need another 8. 55 + 8 = 63 The problem is, the fence (wall) will not be free standing. You'll need three twelve foot 4 x 4 posts (twelve foot long, because four feet of them will be set into the ground.
8' x 20' = 160 sq' that is the formula for area.
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