(8 + x)2 = 64 + 16x + x2
To find "six less than the square of the sum of 5 and a number," we first express the number as ( x ). The sum of 5 and ( x ) is ( 5 + x ). Squaring this sum gives us ( (5 + x)^2 ). Finally, subtracting 6 results in the expression ( (5 + x)^2 - 6 ).
x + y = 48
x + 4 - 8 x - 4
Sum = 3 x centre
It can be, it need not be.
The square of the sum of ( x ) and ( y ) is expressed mathematically as ( (x + y)^2 ). This can be expanded using the formula for the square of a binomial, resulting in ( x^2 + 2xy + y^2 ). Thus, the square of the sum of ( x ) and ( y ) captures both the individual squares of ( x ) and ( y ) as well as twice their product.
There are two solution: -3 and +2.
x+(-8)This simplifies to x-8
To find "six less than the square of the sum of 5 and a number," we first express the number as ( x ). The sum of 5 and ( x ) is ( 5 + x ). Squaring this sum gives us ( (5 + x)^2 ). Finally, subtracting 6 results in the expression ( (5 + x)^2 - 6 ).
It's (x2 + 25).
x + y = 48
x + 4 - 8 x - 4
Sum = 3 x centre
The square of eight is sixty four - not me!
(x+3)2=x2+6x+9
It can be, it need not be.
18 x 18 = 324