±0.82218*i where i is the imaginary square root of -1.
It is: 1/11
The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.
The square root of 1/100 is 1/10
It is i/3 where i is the imaginary number which is the square root of -1.
±0.82218*i where i is the imaginary square root of -1.
It is: 1/11
1 square root of 144 =12 square root of 121=11so 12-11=1
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
1/6 because 121/11=11-5=6=6/1(reciprocal)=1/6
the square root of (1/4) is 1/2
The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.
The square root of 1/100 is 1/10
7 + sqrt(-121) => 7 + sqrt( -1 X 121) => 7 + sqrt(-1) X sqrt(121) => 7 + sqrt(-1) *+/-11 = > 7 +/= 11sqrt(-1) The sqrt(-1) is designated the letter 'i' ( small /lower case 'i'). Hence 7 +/- 11i NB If you can find the 'square root of '-1'' , then the mathemtical world. would like to hear from you.
The square root of 1 over 15 is a constant and so differentiating it gives 0.
It is i/3 where i is the imaginary number which is the square root of -1.
1 over 6