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sqrt(1/121) = ±1/11

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Q: What is the square root of 1 over 121?
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What is the square root of -121 over 179?

±0.82218*i where i is the imaginary square root of -1.


What is the square root of 1 over 121 simplified?

It is: 1/11


What is the square root of 144 minus square root of 121?

1 square root of 144 =12 square root of 121=11so 12-11=1


What is The square root of 25-2times the square root of -36 plus the square root of four - the square root of 121?

Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i


What is the reciprocal of the square root of 121 minus five?

1/6 because 121/11=11-5=6=6/1(reciprocal)=1/6


What is the square root of 1 over 4?

the square root of (1/4) is 1/2


Each side of a square is lengthened by 1 in The area of the new square is 121 square inches Find the length of a side in the original square?

The new square has an area of 121, so the length of a side is the square root of 121, or 11. So the length of the side of the old square was 10.


What is the square root of one over a hundred?

The square root of 1/100 is 1/10


What is the square root of ten over the square root of forty?

Oh, what a happy little question! When you have the square root of ten over the square root of forty, you can simplify it by dividing the square roots. So, the answer is the square root of ten over the square root of forty simplifies to one over the square root of four, which simplifies further to one over two. Just a little math magic to brighten your day!


What is the complex number of 7 plus square root of -121?

7 + sqrt(-121) => 7 + sqrt( -1 X 121) => 7 + sqrt(-1) X sqrt(121) => 7 + sqrt(-1) *+/-11 = > 7 +/= 11sqrt(-1) The sqrt(-1) is designated the letter 'i' ( small /lower case 'i'). Hence 7 +/- 11i NB If you can find the 'square root of '-1'' , then the mathemtical world. would like to hear from you.


Differentiate square root of 1 over 15?

The square root of 1 over 15 is a constant and so differentiating it gives 0.


What is the square root of -1 over 9?

It is i/3 where i is the imaginary number which is the square root of -1.